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0=h^2+37h+36
We move all terms to the left:
0-(h^2+37h+36)=0
We add all the numbers together, and all the variables
-(h^2+37h+36)=0
We get rid of parentheses
-h^2-37h-36=0
We add all the numbers together, and all the variables
-1h^2-37h-36=0
a = -1; b = -37; c = -36;
Δ = b2-4ac
Δ = -372-4·(-1)·(-36)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-35}{2*-1}=\frac{2}{-2} =-1 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+35}{2*-1}=\frac{72}{-2} =-36 $
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